File:Rational sequence with 2 accumulation points.pdf

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Description	English: Shows the sequence (-1)ⁿ·n/(n+1), which has no limit point, but two accumulation points, viz. -1 and +1.
Date	30 December 2013
Source	Own work
Author	Jochen Burghardt
Permission (Reusing this file)	I, the copyright holder of this work, hereby publish it under the following license: This file is licensed under the Creative Commons Attribution-Share Alike 3.0 Unported license. You are free: to share – to copy, distribute and transmit the work to remix – to adapt the work Under the following conditions: attribution – You must give appropriate credit, provide a link to the license, and indicate if changes were made. You may do so in any reasonable manner, but not in any way that suggests the licensor endorses you or your use. share alike – If you remix, transform, or build upon the material, you must distribute your contributions under the same or compatible license as the original. CC BY-SA 3.0 truetrue
Other versions	File:Rational sequence with 2 accumulation points svg.svg

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\end{picture}
\end{document}

C source code to generate sequence members

#include <stdio.h>

static inline void prPts(
    int n)
{
    int i;
    int sg; 

    sg = +1; 
    for (i=0; i<n; ++i) {
        double const v = (double)(i) / (double)(i+1);
        printf(" \\textcolor{cSeq}{");
        printf("\\put(%10.6f,2){",sg*v*100.0);
        printf("\\line(0,-1){2}}}%%\n");
        printf("%%\\textcolor{cSqt}{");
        printf("\\put(%10.6f,5){",sg*v*100.0);
        printf("\\makebox(0,0)[b]{$");
        //printf(sg > 0 ? "+" : "-");
        printf("\\frac{%d}{%d}$}}}%%\n",i,i+1);
        sg = -sg;
    }   
}

int main(
    int argc,
    const char * const argv[argc])
{
    prPts(1000);
    return 0;
}

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current	19:39, 2 January 2014		1,356 × 87 (12 KB)	Jochen Burghardt (talk \| contribs)	{{Information \|Description ={{en\|1=(later)}} \|Source ={{own}} \|Author =Jochen Burghardt \|Date =2013-12-30 \|Permission = \|other_versions = }}

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