File:Symplectic-method-for-keplerian-motion.svg
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Summary
[edit]DescriptionSymplectic-method-for-keplerian-motion.svg |
English: Energy error in numerical solutions of the elliptic Keplerian orbit for e=0.5. The object is at the apocenter at initial time. The time step is 1/128 of the orbital period.
The unit of the horizontal axis is the orbital period. |
Date | |
Source | Own work |
Author | Osanshouo |
Licensing
[edit]I, the copyright holder of this work, hereby publish it under the following license:
This file is licensed under the Creative Commons Attribution 4.0 International license.
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- to share – to copy, distribute and transmit the work
- to remix – to adapt the work
- Under the following conditions:
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Source code
[edit]'''
Solve the Kepler problem $H = p^2/2 - 4 \pi / | x |$.
Code unit:
coordinate: initial semi-major axis $a$
time: orbital period $P$
Output file:
"./symplectic-method-for-keplerian-motion.svg"
'''
import numpy as np
import matplotlib.pyplot as plt
plt.rcParams["text.usetex"] = True
plt.rcParams["font.family"] = "DejaVu Sans"
plt.rcParams["font.size"] = 14
fig = plt.figure()
plt.subplots_adjust(left=0.15, right=0.75)
ax = fig.add_subplot(111)
### parameters ####################
e = 0.5 # eccentricity
dt = 1./128. # time step
t_end = 4 # calculation end time
###################################
def force(x):
r = np.linalg.norm(x)
return -4.*np.pi**2*x/r**3
def solve(method, param):
ts, xs, vs = [0.], [np.array([1.+e, 0])], [np.array([0., 2.*np.pi*np.sqrt((1-e)/(1+e))])]
while ts[-1] < t_end:
x, v = method(xs[-1], vs[-1])
ts.append(ts[-1] + dt)
xs.append(x)
vs.append(v)
ts, xs, vs = np.array(ts), np.array(xs), np.array(vs)
energy = np.sum(vs**2, axis=1)/2. - 4.*np.pi**2/np.linalg.norm(xs, axis=1)
ax.plot(ts, np.fabs((energy - energy[0])/energy[0]), **param)
return 0
# Euler
def euler(x, v):
return x + v*dt, v + force(x)*dt
solve(euler, {"label":"Euler"})
# RK4
def rk4(x, v):
dx1, dv1 = v, force(x)
dx2, dv2 = v+dv1*dt/2., force(x+dx1*dt/2.)
dx3, dv3 = v+dv2*dt/2., force(x+dx2*dt/2.)
dx4, dv4 = v+dv3*dt, force(x+dx3*dt )
return x + (dx1 + 2.*(dx2 + dx3) + dx4)*dt/6., v + (dv1 + 2.*(dv2 + dv3) + dv4)*dt/6.,
solve(rk4, {"label": "RK4"})
# symp1
def symp1(x, v):
x = x + v*dt
return x, v + force(x)*dt
solve(symp1, {"label":"Symp1", "ls":"-."})
# symp2
def symp2(x, v, dt=dt):
x = x + v*dt/2.
v = v + force(x)*dt
return x + v*dt/2., v
solve(symp2, {"label":"Symp2", "ls":":"})
# symp4
def symp4(x, v):
d1 = 1./(2. - np.cbrt(2.))
d2 = 1. - 2.*d1
x, v = symp2(x, v, dt=dt*d1)
x, v = symp2(x, v, dt=dt*d2)
return symp2(x, v, dt=dt*d1)
solve(symp4, {"label":"Symp4", "ls":"-."})
ax.set_title("$e={}$".format(e))
ax.set_xlabel(r"time $t/P$")
ax.set_ylabel(r"energy error $\left| \Delta E / E_0 \right|$")
ax.set_yscale("log")
ax.set_xlim([0, t_end])
ax.set_ylim([1e-7, 2])
ax.grid()
ax.legend(bbox_to_anchor=(1.05, 1), loc='upper left', borderaxespad=0, fontsize=14)
plt.savefig("symplectic-method-for-keplerian-motion.svg")
plt.show()
plt.close()
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Date/Time | Thumbnail | Dimensions | User | Comment | |
---|---|---|---|---|---|
current | 13:17, 2 June 2020 | 576 × 432 (71 KB) | Osanshouo (talk | contribs) | Uploaded own work with UploadWizard |
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